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Calculate the molarity of (a) 6.57 g of methanol (CH3OH) in 150. mL of solution and...

Calculate the molarity of (a) 6.57 g of methanol (CH3OH) in 150. mL of solution and (b) 10.4 g of calcium chloride in 220. mL of solution.

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Answer #1

molarity = W*1000/G.M.Wt *volume of solution

weight of CH3OH (w) = 6.57g

G.M.Wt of CH3OH = 32g/mole

volume of solution = 150ml

molarity = W*1000/G.M.Wt *volume of solution

             = 6.57*1000/32*150   = 1.37M

b.

molarity = W*1000/G.M.Wt *volume of solution

weight of CaCl2 (w) = 10.4g

G.M.Wt of CaCl2 = 111g/mole

volume of solution = 220ml

molarity = W*1000/G.M.Wt *volume of solution

              = 10.4*1000/111*220 = 0.426M

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