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If, I have an unknown quantity of gas held at temperature 900K in a container with...

If, I have an unknown quantity of gas held at temperature 900K in a container with a volume of 25.0 liters and a pressure of 56 atm, how many moles of gas do I have?

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Answer #1

Assume ideal behavior and use the ideal gas law:

PV = nRT where P = pressure of the gas in atmospheres; V = volume of the gas in L, n = quantity of the gas in moles and T = temperature of the gas in K. R is the gas constant having a value of 0.082 L-atm/mol.K.

Given, P = 56 atm, V = 25.0 L and T = 900 K; plug in values to obtain

n = PV/RT = (56 atm)*(25.0 L)/(0.082 L-atm/mol.K).(900 K) = 18.97 moles ≈ 19.0 moles.

We have approx. 19.0 moles of the unknown gas (ans).

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