Question

(a) Consider the combustion of ethylene, given below. C2H4(g) + 3 O2(g) ? 2 CO2 (g)...

(a) Consider the combustion of ethylene, given below.

C2H4(g) + 3 O2(g) ? 2 CO2 (g) + 2 H2O (g)

If the concentration of C2H4 is decreasing at the rate of 0.26 M/s, what are the rates of change in the concentrations of CO2 and H2O?
CO2

(b) The rate of decrease in N2H4 partial pressure in a closed reaction vessel from the following reaction is 41 torr/hr.

N2H4 (g) + H2 (g) ? 2 NH3 (g)

What are the rates of change of NH3 partial pressure and total pressure in the vessel?
NH3

Homework Answers

Answer #1

(a)

The given reaction is

C2H4(g) + 3 O2(g) ? 2 CO2 (g) + 2 H2O (g)

rate = -d[C2H4]/dt = -1/3d[O2]/dt = +1/2d[CO2]/dt = +1/2d[H2O]/dt

Given, -d[C2H4]/dt = 0.26 M/s

Rate of change in concentration of CO2 is

-d[C2H4]/dt = +1/2d[CO2]/dt

0.26 M/s = +1/2d[CO2]/dt

d[CO2]/dt = 2 x 0.26 = 0.52 M/s

Rate of change in concentration of H2O is

-d[C2H4]/dt = +1/2d[H2O]/dt

0.26 M/s = +1/2d[H2O]/dt

+1/2d[H2O]/dt =  2 x 0.26 = 0.52 M/s

--------------------------------------------

(b)

The given reaction is

N2H4 (g) + H2 (g) ? 2 NH3 (g)

rate = -d[N2H4]/dt ] = -d[H2]/dt = +1/2d[NH3]/dt

-d[N2H4]/dt ] = 41 torr/hr

The rate of change of NH3 partial pressure is

-d[N2H4]/dt ] = +1/2d[NH3]/dt

d[NH3]/dt = 2 x -d[N2H4]/dt ] = 2 x 41 torr/hr = 82 torr/hr

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