Determine the end (final) value of n in a hydrogen atom transition, if the electron starts in n = 2 and the atom absorbs a photon of light with a frequency of 4.57 × 10 14 Hz. (This question has already been posted, however, the answers for it dont match the options).
We know that frequency , v = c / λ
Where
c = speed of light = 3x 108m/s
λ = wave length = ?
v = Freqency = 4.57x1014 Hz
Plug the values we get λ = c / v = 6.564x10-7 m
Also From Rydburg's Equation , 1/ λ = R[(1/ni2) – (1/nf2)]
Where R = Rydburg's constant = 10.96
x106 m-1
λ = wavelength = 6.564x10-7 m
ni = 2
nf = ?
Plug the values we get [(1/ni2) –
(1/nf2)] = 1 / (λ R) = 0.139
[(1/22) – (1/nf2)] = 0.139
(1/nf2) = 0.111
nf2=9
nf = 3
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