pKa = -log (Ka)
= log ( 1.1 x 10^-2)
= 1.95
Using Henderson Handerson Hasselbach equation for buffers, ie
pH = pKa + log [base] / [acid]
Where base = NaClO2
Acid = HClO2
Putting the respective values, we get
1.89 = 1.95 + log ( mass of base /( molar mass of base x volume of solution in litres)) / 1.70 M
1. 89 - 1.95 = log (mass of base / (90.44 gmol-1 x 0.25 L)) / 1.70 M
10^-0.06 = mass of base / 38.437g
0.87 x 38.47 g = mass of base
33 g = mass of base ie NaClO2
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