Using the information below determine the change in enthalpy for the following reaction:
2NO(g) + 5 H2(g) → 2NH3(g) + 2H2O(l)
H2(g) + ½ O2(g) → H2O(l) ∆H°= -285.8kJ
N2(g) + O2(g) → 2NO(g) ∆H°= +180.5 kJ
2NH3(g) → N2(g) + 3H2(g) ∆H°= + 92.22 kJ
please explain step by step! thanks!
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