which contains more molecules of a 1 L solution of 0.5M solution of NaF or 0.5 M of H3PO4
No. of moles = Molarity * volume in litres
for both of them its equal
but when in solution they both will dissociate
NaF(aq) = Na+(aq) + F-(aq) being a strong electrolyte it will
dissociate completly and form 2 times moles of NaF ions in solution
as its Ksp(solubility product) is very high
although it has 3 H+ and on PO4- to be produced from a single
molecule of H3PO4 but Ksp of H3PO4 is quite low as can be seen from
figure below and hence it won't dissociate much and forming limited
ions in solution
NaF contains more
ions in solution than H3PO4
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