Let us observe the separation scheme for the cations provided. For the background information, is group 2 cation and the remaining three cations are of Group 3. The scheme is given below-
Now as CuS is separated out, we would be left with the solution containing . Now there is no feasible way of separation of these three cations in a mixture. The only way out here is that, as we already know we have the three cations, we simply divide the sample! Let us see the scheme below-
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