if we have Body centered orthorhombicwith unit cell
dimenisons (3,4,6)A , find:
spacing between planes (210)?
Packing fractions?
reciprocal lattice vectors ?
answer : for orthorombic bcc structure we have the packing fraction as
Packing fraction = (2 x 4/3 R3 ) / a3 , but R = (3 / 4) a
substituting we get packing fraction = (8 x 3 3 a3 ) / ( 3 x 64 x a3 ) = 0.68
hence packing fraction for bcc = 0.68
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