Question

How many grams of water vapor would be required to occupy a 1716 mL flask at 0.98 atm and 96 degrees Celcius? Record your answer in scientific notation to 2 decimal spaces.

Answer 1

According to Ideal gas equation

PV = nRT

P = 0.98 atm, V = 1716 mL =>1.716 L

T = 96 + 273 = 369 K, R = 0.0821 L.atm/mol.K

n = PV/RT

   = (0.98*1.716)/(0.0821*369)

   = 0.0555 moles.

mass of water = moles*molarmass

                       = 0.0555*18

                       = 9.99*10^-1 g