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For Zn+Ag2O = ZnO+Ag Write out Nerst equation for both half cells (find E)Predict how the...

For Zn+Ag2O = ZnO+Ag Write out Nerst equation for both half cells (find E)Predict how the voltage of the battery will change as the starting concentrations decrease. Draw the galvonic cell for the reaction. Find Eo also.

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Answer #1

The half reactions will be

Oxidation : Zn --> Zn+2 + 2e [anode]

Reduction : Ag+ + e --> Ag(s)   [cathode]

Overall reaction will be

Zn(s) + 2Ag+ --> Zn+2 + 2Ag(s)
Cathodic nernst equation will be

Ecathode = E0cathode - 0.0592 / 2 log 1/[Ag+]^2

Anodic nernst equation will be

Eanode = E0cathode - 0.0592 / 2 log 1/[Zn+2]

Ecell = E0cell - 0.0592 /2 9log[[Zn+2] / [Ag+]^2

So as concentration is decreased the initial concentration of Ag+ will decrease and i will increase the EMF of cell.

E0cell = E0cathode - E0anode

E0cell = 0.80 -(-0.76) = +1.56

The cell can be written as

Zn(s) / ZnO (M1) // Ag2O(M2) / Ag(s)

Nernst equation is

Ecell = E0cell - 0.0592 / n log Q

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