Question

Calculate the [H3O+] of a 1.99 M HBrO solution at 25 ºC.

Calculate the [H3O+] of a 1.99 M HBrO solution at 25 ºC.

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Answer #1

                         HBrO + H2O <=> H3O+ + BrO-

initial          I       1.99 M------------------ 0 ------ 0

change       C        -x    ------------------ +x ------ +x

equilibrium E     1.99-x ------------------ +x ------- +x                     Ka for HBrO at 25 oC = 2.8 x 10-9


Ka = [H3O+][BrO-]/ [HBrO] = ( x)(x )/ (1.99-x) = 2.8 x 10-9

Ka is very small hence (1.99-x) term becomes 1.99

( x)(x )/ (1.99) = 2.8 x 10-9 solving for x gives

x = 7.4645 X 10-5

Hence [H3O+] = 7.4645 X 10-5

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