Use the equation give to solve the following problems 2 KMnO4 + 16 HCl --> 5 Cl2 + 2KCl + 2 MnCl2 + 8 H2O: 1.) How many moles of HCl are required to react with 45 grams of KMnO4? 2.) How many Cl2 molecules will be produced using 5.0 mol of KMnO4? 3.) To produce 55.0 grams of MnCl2, what weight of HCl will be reacted? 4.) How many moles of water will be produced when 7.0 mol of KMnO4 are consumed? 5.) What is the maximum weight of Cl2 that can be produced by reacting 35.0 grams of KMnO4 with 45.0 grams of HCl?
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