If a silver wire is placed in a beaker containing 1 M Cu(NO3)2, what will happen and why?
answer : no reaction takes place
explanation:
Ag electode potential = +0.80 V
Cu electronpotential = +0.34 V
favourable reaction in between these two
oxidation at anode : Cu --------------> Cu+2 +2e-
reduction at cathode : 2 Ag+ +2e- --------------> 2Ag
Copper electrode potential is lesser than Ag . here we have Cu+2 and Ag . so there is no reaction between these two nothing will happens.
reverse is possible . that means Cu is placed in AgNO3 , Ag will deposit
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