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What is the pH of a solution prepared by mixing 25.00 mL of 0.10 M CH3CO2H...

What is the pH of a solution prepared by mixing 25.00 mL of 0.10 M CH3CO2H with 25.00 mL of 0.040 M CH3CO2Na? Assume that the volume of the solutions are additive and that K a = 1.8 × 10-5 for CH3CO2H.

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Answer #1

PKa = -logKa

        = -log1.8*10-5

       = -log1.8+5log10

      = -0.2552+5 = 4.7447

no of millimoles of CH3COONa = 25*0.04 = 1

no of millimoles of CH3COOH = 25*0.1 = 2.5

total volume = 25 + 25 = 50ml

PH    = PKa + log[CH3COONa]/[CH3COOH]

         = 4.7447+ log1/50/2.5/50

         = 4.7447 + log1/2.5

       = 4.7447 -0.3979

PH     = 4.3468

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