Use the information in the table below to determine DGofor the reaction
2NH3(g) + 2O2(g) --> N2O(g) + 3H2O(l)
DGo (kJ) |
|
N2(g) + 3H2(g) --> 2NH3(g) |
-33.0 |
4NH3(g) + 5O2(g) --> 4NO(g) + 6H2O(l) |
-1010.0 |
N2(g) + O2(g) --> 2NO(g) |
174.9 |
N2(g) + 2O2(g) --> 2NO2(g) |
102.6 |
2N2(g) + O2(g) --> 2N2O(g) |
204.2 |
(4NH3(g) + 5O2(g) --> 4NO(g) + 6H2O(l))*1/2 DG1 = -1010/2 =
(2N2(g) + O2(g) --> 2N2O(g) )*1/2 DG2 = 204.2/2
2NO(g)
----> N2(g) +
O2(g)
dg3 = -174.9
--------------------------------------------
2NH3(g) + 2O2(g) --> N2O(g) + 3H2O(l) DG0 = (-1010/2)+(204.2/2)+(-174.9) = -577.8 Kj
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