Question

How can I determine the moles of sodium methoxide based on this information:

10 mL 2% sodium methoxide solution is prepared by adding 0.18 g of NaOH to 10 mL 99% MeOH

Answer 1

moles of NaOH = 0.18 / 40 = 0.0045

mass of MeOH = 99 g

moles of MeOH = 99 / 32 = 3.09

CH3OH    +    NaOH    ---------------> CH3ONa   +   H2O

    1                   1                                     1

3.09         0.0045                             

here limiting reagent is NaOH. because moles of NaOH is low.

moles of CH3ONa = 0.0045