Silver metal consists of two isotopes: 107Ag (isotopic mass=106.9051amu) and 109Ag (isotopic mass=108.9048amu). If the average of atomic mass of silver is 107.8682 amu, calculate the % by mass of each isotope in silver metal.
please set up this problem explaining along the way and then answer. Thanks!
The problem is solved in a simple manner by taking the % as x and (1-x ) for the 107 Ag and 109 Ag Isotope and solving the mathematical equation and from there we get the value of x which will give us the percentage of 107Ag isotope and 100-% x will give us the % of 109 Ag.
Hence x= 51.8 % of 107 Ag and 100-51.8% =48.2% of 109 Ag.
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