a mixture of KCl and KNO3 is 44.2% potassium by mass. The percent of KCL in the mixture is?
mixture = KCl + KNO3
each gives 1 K
mass % K = 44.2%
mass KCl = 74.55 g
mass KNO3 = 101.10 g
mass% K in KCl = 39.1 g x 100/74.55 g = 52.45%
mass% K in KNO3 = 39.1 g x 100/101.10 g = 38.7%
let say we have x fraction amount of KCl in the mixture,
then we would have 1-x fraction amount of KNO3 left in the mixture
52.45x + 38.7(1-x) = 44.2
52.45x+ 38.7 - 38.7x = 44.2
x = (5.5/13.75) = 0.4 fraction
the percent KCl in the mixture = 0.4 x 100 = 40%
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