1.
23.5 g Ti = 23.5/ 183.84
2.
0.254 moles of Iron (III) chloride = 0.254 * 162.2
3.
0.635 grams = 0.635 grams *NA = 0.635 grams * 6.023 * 10^23
4.
Ca3 (PO4 )2 ---> 3Ca+2 + 2 PO4-2
Hence moles of Ca3 (PO4 )2 = 0.864/2
5.
0.0011 g Mg ? ? g C
0.0011 g Mg -> mol Mg -> mol C -> g C
24.3050 g Mg = 1 mol Mg
1 mol Mg ? 55 mol C
1 mol C = 12.011 g C
6.
7.
118.7g Sn= 1 mol Sn; 35,45g Cl= 1 mol Cl
mass of Sn= 1.17g Sn; mass of Cl= 2.57g-1.17g= 1.40g Cl
1.17g Sn (1 mol Sn/ 118.7g Sn)= 0.00986 mol Sn
1.40 g Cl (1 mol Cl/35.45g Cl)= 0.0395 mol Cl
(0.00986/0.00986)= Sn????; (0.0395/0.00986)= Cl????
Empirical formula = SnCl4
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