An aqueous solution of HC3H5O3 is prepared by dissolving 0.1 moles of lactic acid, HC3H5O3, in sufficient water to yeild 1.0 liter of solution. The pH of resulting solution is 2.43.....Calculate the Ka for HC3H5O3, lactic acid:......a) Write a balanced equation for the dissociation of HC3H5O3......b) Write the equilibrium constant Ka=........c) Solve for Ka for lactic acid........d) What is the % dissociation for the weak acid, HC3H5O3......Please include all the steps...I am really struggling with this chapter...Thank you:)
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