moles of KIO3 = mass / molar mass = 0.6013 / 214
= 2.81 x 10^-3
6H+ +IO3-(Aq) +8I-(Aq) -------------> 3I3-(Aq) +3H20
6 mol HCl --------------------> 1 mol KIO3 or IO3-
x mol HCl -----------------> 2.81 x 10^-3 mol KIO3
x = 6 x 2.81 x 10^-3 = 0.0169
moles of HCl = 0.0169
molarity = 3.00 M
volume = moles / molarity
= 0.0169 / 3.00
= 5.62 x 10^-3 L
volume of HCl = 5.62 mL
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