1) Convert Ao to cm:
1.97 Ao x (1 cm/108 Ao) = 1.97 x 10¯8cm
2) Calculate the volume of the unit cell:
(1.97 x 10¯8 cm)3 = 7.645 x 10¯24 cm3
3) Calculate the average mass of one atom of Ca:
40.078 g mol¯1 divided by 6.022 x 1023 atoms mol¯1 = 6.655 x 10¯23 g
4) Calculate the mass of the 4 Calcium atoms in the face-centered cubic unit cell:
6.655 x 10¯23 g times 4 = 2.66 x 10¯22 g
5) Calculate the density (value from step 4 divided by value from step 2):
2.66 x 10¯22 g / 7.645 x 10¯24 cm3 = 34.79 g/cm3
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