Question

Find ΔG for melting ice at 0°C and 100 atm. At this temperature and pressure conditions, the densities of the ice and liquid water are 0.9168 g/cm³ and 1.000 g/cm³ , respectively

Answer 1

100 g of water is 100/18 = 5.556 moles

H = n H_fus

H = 5.556 x 6.0 kJ/mol

H = 33.33 kJ

S^o = (n x H_fus)/T

S^o = (5.556 x 6.0)/273

S^o = 0.122 kJ/K

G = H - T S^o

G = 33.33kJ - 273 x 0.122 J/K

G = 0kJ