Question

# Aqueous sulfuric acid H2SO4 will react with solid sodium hydroxide NaOH to produce aqueous sodium sulfate...

Aqueous sulfuric acid H2SO4 will react with solid sodium hydroxide NaOH to produce aqueous sodium sulfate Na2SO4 and liquid water H2O . Suppose 81. g of sulfuric acid is mixed with 36.5 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits.

First we pass both reactants to moles:

81 grams of H2SO4 * (1 mol / 98.079 grams) = 0.82586 moles of H2SO4

36.5 grams of NaOH * (1 mol / 40 grams) = 0.9125 moles of NaOH

Then we express the reaction:

2NaOH + H2SO4 -> 2H2O + Na2SO4

We now determine which is the limiting reactant. In this case, the limiting reactant is sodium hydroxide, as it will run out first.

We convert the moles of NaOH to moles of water:

0.9125 moles of NaOH * (2 moles of H2O / 2 moles of NaOH) = 0.9125 moles of H2O

We convert these moles to grams:

0.9125 moles of H2O * (18 grams / mol) = 16.425 grams

To three significant digits, 16.4 grams.

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