Question

A quantity of CO gas occupies a volume of 0.66 L at 1.3atm and 303 K . The pressure of the gas is lowered and its temperature is raised until its volume is 2.9 L .Find the density of the CO under the new conditions.

Answer 1

Given,

Initial Volume of CO = V = 0.66 L

Initial Pressure of CO = P = 1.3 atm

Initial Temperature of CO = T = 303 K

We know that,

PV = nRT

=> 1.3 x 0.66 = n x 0.0821 x 303

=> n = 0.0345 moles

New Volume = 2.9 L

PV = nRT

=> PV = (m/M) RT

=> PM = dRT

where, d = m / V = density

=> d = P' x M / R x T'

where P' and T' are new Pressure and Temp.

PV / T = P'V' / T'

=> 1.3 x 0.66 / 303 = P' x 2.9 / T'

=> P' / T' = 9.76 x 10^-4

=> d = (M / R) x (P' / T')

=> d = (28 / 0.0821) x (9.76 x 10^-4)

=> d = 0.333 g / L = 3.33 x 10^-4 g / mL