take 30 moles methane in calorimeter with known heat capacity.
heat the compound then temperature of calorimeter increase which indicates how much heat is released.
now heat gained by calorimeter = heat lost by methane.
mCdeltaT of calorimeter = mCdeltaT of methane.
we know mass of calorimeter and mass of methane.
we knoe change in temperature.
we know heat capacity of calorimeter.
we will find the heat capacity of methane for 30 moles by using above equation.
if we know for 30 moles we can find for 1 mole easily.
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