Question

At a given temperature, Kp = 19 for the reaction, N2O4(g) <=> 2 NO2(g) For which...

At a given temperature, Kp = 19 for the reaction,
N2O4(g) <=> 2 NO2(g)
For which system is the value of Kp = 361?

Please show work so I can figure out what I am doing wrong. Thank you!

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Homework Answers

Answer #1

For given transformation,

N2O4(g) <======> 2 NO2(g)

Equilibrium constant Kp can be written as,

Kp = (PNO2)2/(PN2O4)

And

Kp =19 given

So, (PNO2)2/(PN2O4) = 19

Squaring on both side we get,

[(PNO2)2/(PN2O4)]2 = (19)2

(PNO2)4/(PN2O4)2 = 361

(PNO2)4/(PN2O4)2 = Pk’

This expression indicate, the stoichiometric transformation,

2N2O4(g) <======= > 4NO2(g)

Hence for this 2N2O4(g) <======= > 4NO2(g) system Kp =361.

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