Calculate the standard enthalpy of formation of liquid water (H2O) using the following thermochemical information:
4 B(s) + 3 O2(g) 2 B2O3(s) H = -2509.1 kJ
B2H6(g) + 3 O2(g) B2O3(s) + 3 H2O(l) H = -2147.5 kJ
B2H6(g) 2 B(s) + 3 H2(g) H = -35.4 kJ
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