Question

# How many grams of magnesium nitrate can be produced from 50.0 mL of a 2.0 mol/L...

How many grams of magnesium nitrate can be produced from 50.0 mL of a 2.0 mol/L nitric acid solution reacting with excess magnesium carbonate?

first write the balanced equation

MgCO3 (aq) + 2HNO3 (aq) ----> Mg(NO3)2 (aq) + H2O (l) + CO2 (g)

from th ebalanced equation it is clear hat for one mole of Mg(NO3)2 2 moles of HNO3 required

he said excess magnisium carbo nate so dont bauther about that

no of moles of HNO3 = molarity of HNO3 x volume of HNO3 in liters

= 2.0 mol/L x 0.05 L

= 0.1 mol

from 0.1 mol of HNO3 0.1/2 = 0.05 moles of Mg(NO3)2 will fom

grams of Mg(NO3)2 = moles of Mg(NO3)2 x molar mass of Mg(NO3)2

= 0.05 mol x 86.31 g/mol

= 4.32 grams

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