0.50 g of sodium hydroxide (NaOH) pellets are dissolved in water to make 6.0 L of solution. What is the pH of this solution? Express the pH numerically to two decimal places.
mass of NaOH = 0.50 g
molar mass of NaOH = 40 g/mol
moles of NaOH = mass / molar mass
= 0.50 / 40
= 0.0125
volume = 6.0 L
molarity = moles / volume
= 0.0125 / 6.0
= 2.08 x 10^-3 M
[OH-] = 2.08 x 10^-3 M
pOH = -log [OH-] = -log ( 2.08 x 10^-3 )
pOH = 2.68
pH + pOH = 14
pH = 11.32
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