Question

Suppose you started with 0.105 g of cholesterol (solid), and 0.119 mL of nonanoyl chloride (pure liquid). Calculate the theoretical yield (in grams) of cholesteryl nonanoate. Give your answer to three decimal places;

Answer 1

1 mole of cholesterol reacts with 1 mole of nonanoyl chloride to form 1 mole of cholesteryl nonanoate
Cholesterol has molar mass of 386.7 g/mol. 0.105 g of cholesterol corresponds to
moles
The molar mass of nonanoyl chloride is 176.7 g/mol. Its density is around 1 g/ml
0.119 mL of nonanoyl chloride are approximately equal to 0.119 g. Number of moles of nonanoyl chloride moles.
Thus, cholesterol is the limiting reagent and nonanoyl chloride is present in excess.
Number of moles of cholesteryl nonanoate formed = 0.000272
Molar mass of cholesteryl nonanoate = 526.9 g/mol
Mass of cholesteryl nonanoate
Hence, the theoretical yield (in grams) of cholesteryl nonanoate = 0.143 g.