Question

Part A 3.41×10−2M  HNO3. Express the pH of the solution to three decimal places. pH = _____...

Part A

3.41×10−2M  HNO3.

Express the pH of the solution to three decimal places.

pH = _____

Part B

0.260 g of HClO3 in 2.60 L of solution.

Express the pH of the solution to three decimal places.

pH = _____

Part C

10.00 mL of 1.70 M  HCl diluted to 0.520 L .

Express the pH of the solution to three decimal places.

pH =_____

Part D

A mixture formed by adding 41.0 mL of 2.5×10−2M  HCl to 160 mL of 1.0×10−2M HI.

Express the pH of the solution to two decimal places.

pH = _____

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Homework Answers

Answer #1

pH= -log[H+]

part A
pH=-log[H+]=-log[3.41*10^-2] =1.467

part B
Moles= 0.260/molar mass of HClO3 = 0.260/84.5
Molarity= moles/volume = 0.260/84.5 *1/2.60 = 0.00118
pH=-log[H+]=-log[0.00118] =2.928

part C
Moles= 1.70*10ml = 17m moles
Molarity= moles/volume = 17m moles/520ml =0.0327
pH=-log[H+]=-log[0.0327 ] =1.485


part D
total Moles=2.5*10^-2*41ml+ 1*10^-2*160ml = 2.625m moles
Molarity= moles/volume =2.625m moles/(41+160)ml =0.01306
pH=-log[H+]=-log[0.01306 ] =1.88

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