Question

The osmotic pressure of a 10.811 mM solution of (NH4)3PO4 is 482.914 mm Hg at 11.41...

The osmotic pressure of a 10.811 mM solution of (NH4)3PO4 is 482.914 mm Hg at 11.41 °C. How many ions per formula unit of (NH4)3PO4 must there be? The compound may not be completely ionic.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A 500.0 mL solution of NaNO3 in water has a vapor pressure of 21.445 mm Hg...
A 500.0 mL solution of NaNO3 in water has a vapor pressure of 21.445 mm Hg at 25°C. How many grams of NaNO3 (molar mass = 84.994 g/mol) were added to the water if the vapor pressure of pure water at 25°C is 23.76 mm Hg. Assume the volume of the water (d = 1.000 g/mL) is the same as the volume of the solution.
The net filtration pressure in Bob’s kidneys was 11 mm Hg, but it changed because hydrostatic...
The net filtration pressure in Bob’s kidneys was 11 mm Hg, but it changed because hydrostatic pressure in the glomerulus increased by 3 mm Hg, while the colloid osmotic pressure in the glomerulus decreased by 1 mm Hg. As a result of these alterations, Bob’s net filtration pressure ________ by _________. Choose the best answer: (a) increased; 3 mm Hg (b) increased; 4 mm Hg (c) decreased; 4 mm Hg (d) increased; 2 mm Hg (e) decreased; 2 mm Hg
Calculate the osmotic pressure of a magnesium citrate laxative solution containing 28.0 g of magnesium citrate...
Calculate the osmotic pressure of a magnesium citrate laxative solution containing 28.0 g of magnesium citrate in 225 mL of solution at 37 ∘C (approximate body temperature). Assume complete dissociation of the ionic compound.
Air is dried from a partial pressure of 50 mm Hg of water vapor to a...
Air is dried from a partial pressure of 50 mm Hg of water vapor to a partial pressure of 10 mm Hg. The temperature of the entering air is 524°F and the pressure is constant at 760 mm Hg. How many gallons of liquid water are removed per 1000 ft3 of entering air?
The vapor pressure of ethanol is 54.68 mm Hg at 25°C. How many grams of estrogen...
The vapor pressure of ethanol is 54.68 mm Hg at 25°C. How many grams of estrogen (estradiol), C18H24O2, a nonvolatile, nonelectrolyte (MW = 272.4 g/mol), must be added to 203.1 grams of ethanol to reduce the vapor pressure to 53.09 mm Hg ? ethanol = CH3CH2OH = 46.07 g/mol.
The vapor pressure of chloroform is 173.11 mm Hg at 25°C. How many grams of aspirin,...
The vapor pressure of chloroform is 173.11 mm Hg at 25°C. How many grams of aspirin, C9H8O4, a nonvolatile, nonelectrolyte (MW = 180.1 g/mol), must be added to 289.1 grams of chloroform to reduce the vapor pressure to 169.35 mm Hg ? chloroform = CHCl3 = 119.40 g/mol. _ g aspirin
The vapor pressure of benzene is 73.03 mm Hg at 25°C. How many grams of estrogen...
The vapor pressure of benzene is 73.03 mm Hg at 25°C. How many grams of estrogen (estradiol), C18H24O2, a nonvolatile, nonelectrolyte (MW = 272.4 g/mol), must be added to 240.8 grams of benzene to reduce the vapor pressure to 71.04 mm Hg ? benzene = C6H6 = 78.12 g/mol. ________g estrogen
The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25°C. How many grams...
The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25°C. How many grams of testosterone, C19H28O2, a nonvolatile, nonelectrolyte (MW = 288.4 g/mol), must be added to 198.3 grams of diethyl ether to reduce the vapor pressure to 457.31 mm Hg ? diethyl ether = CH3CH2OCH2CH3 = 74.12 g/mol. g testosterone
Raoult’s Law Calculations The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25°C....
Raoult’s Law Calculations The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25°C. How many grams of aspirin, C9H8O4, a nonvolatile, nonelectrolyte (MW = 180.1 g/mol), must be added to 224.2 grams of diethyl ether to reduce the vapor pressure to 458.89 mm Hg ? diethyl ether = CH3CH2OCH2CH3 = 74.12 g/mol. g aspirin
The vapor pressure of water at 25 degrees Celsius is 23.76 mm of Hg; Kf for...
The vapor pressure of water at 25 degrees Celsius is 23.76 mm of Hg; Kf for water is 1.86 (degree Celsius kg/mol). The normal boiling point of chloroform is 61.0 degrees Celsius and Kb is 3.63 (degree Celsius kg/mol) R=0.08206 (L atm/mol.k). 1. What is the vapor pressure of a solution on 10.0g of NaNO3 in 25.0g of water? 2. What is the freezing point of a 0.20 m aqueous solution of sucrose at 1 atm pressure? 3. What is...