The weak acid HA is determined to be 9.14% dissociated when the initial concentration of HA is 0.0200M. Calculate Ka for this acid.
HA + H2O <===> H3O+ + A-
9.14% dissociated means
(concentration of [H3O+] / concentration of [HA]) x 100 = 9.14
(concentration of [H3O+] /0.02) x 100 = 9.14
(concentration of [H3O+] /0.02) = 9.14 / 100
(concentration of [H3O+] /0.02) = 0.0914
concentration of [H3O+] = 0.0914 x 0.02
concentration of [H3O+] = 0.00183 M
from the equation [H3O+] = [A-] = 0.00183
concentration of HA at equilibrium = 0.02 - 0.00183 = 0.01817
now wxpression of Ka
Ka = [H3O+][A-] / [HA]
Ka = [0.00183][0.00183] / [0.01817]
Ka = 1.84 x 10-4
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