Question

The weak acid HA is determined to be 9.14% dissociated when the initial concentration of HA...

The weak acid HA is determined to be 9.14% dissociated when the initial concentration of HA is 0.0200M. Calculate Ka for this acid.

Homework Answers

Answer #1

HA + H2O <===> H3O+ + A-

9.14% dissociated means

(concentration of [H3O+] / concentration of [HA]) x 100 = 9.14

(concentration of [H3O+] /0.02) x 100 = 9.14

(concentration of [H3O+] /0.02) = 9.14 / 100

(concentration of [H3O+] /0.02) = 0.0914

concentration of [H3O+] = 0.0914 x 0.02

concentration of [H3O+] = 0.00183 M

from the equation [H3O+] = [A-] = 0.00183

concentration of HA at equilibrium = 0.02 - 0.00183 = 0.01817

now wxpression of Ka

Ka = [H3O+][A-] / [HA]

Ka = [0.00183][0.00183] / [0.01817]

Ka = 1.84 x 10-4

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