Question

In an experiment to determine the molar mass of dichlorobenzene using freezing point depression of solvent...

In an experiment to determine the molar mass of dichlorobenzene using freezing point depression of solvent cyclohexane, a student uses 10 mL of cyclohexane(density 0.779 g/mL) and obtains an average freezing point of 5.75°C. she graphically determine is the new freezing point to be 2.8°C by setting equation of two lines equal to each other what is her delta Tf? if she uses a total of 0.2301 g of dichlorobenzene what is a calculated molecular weight for the solute? what is percent error from actual molecular weight of solute? is this a reasonable result?

Homework Answers

Answer #1

dichlorobenzene = 147.01 g/mol approx

V = 10 mL of cyclohexane solvent

D = m/V; so

mass = D*V = 0.779 *10 = 7.79 g of cylohexane

mass in kg = 7.79*10^-3 kg of cyclohexane

m = 0.2301 g of solute

Tf(normal) = 5.75°C

Tf(mix) = 2.8°C

dT = 5.75-2.8 = 2.95 °C

for...

hexane = –20.2

so

dT = Kf*m

m = mol of soute / kg solvent

- 2.95 = -20.2 * mol of solute / ( 7.79*10^-3)

mol of solut e= 2.95 /20.2 * ( 7.79*10^-3) = 0.00113764

MW = mass/mol = 0.2301 /0.00113764 = 202.26 g /mol

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