When 1382 J of heat energy is added to 38.6 g of ethanol, C2H6O, the temperature increases by 14.6 °C. Calculate the molar heat capacity of C2H6O.
In the problem the heat is added to ethanol (C2H6O) and the temperature increases.
Given,
heat, Q = 1382 J
mass,m = 38.6 g
change in temperature, T = 14.6 oC
As molecular mass of ethanol is = 46 g
therefore the number of moles = 38.6/46 = 0.8391 mol
As we know, Q = nCvT
1382 = 0.8391xCvx14.6
Calculating for Cv = 1382/(14.6x0.8391)
Cv = 112.8
Hence molar heat capacity (Cv) came out to be 112.8 Jmol-1oC-1
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