Question

When 1382 J of heat energy is added to 38.6 g of ethanol, C2H6O, the temperature increases by 14.6 °C. Calculate the molar heat capacity of C2H6O.

Answer #1

In the problem the heat is added to ethanol
(C_{2}H_{6}O) and the temperature increases.

Given,

heat, Q = 1382 J

mass,m = 38.6 g

change in temperature, T =
14.6 ^{o}C

As molecular mass of ethanol is = 46 g

therefore the number of moles = 38.6/46 = 0.8391 mol

As we know, Q =
nC_{v}T

1382 = 0.8391xC_{v}x14.6

Calculating for C_{v} =
1382/(14.6x0.8391)

C_{v} = 112.8

Hence molar heat capacity (C_{v}) came out to be 112.8
Jmol^{-1}^{o}C^{-1}

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