Question

Calculate the equilibrium concentration of Ag+ (aq) in a solution that is initially 0.200 M AgNO3...

Calculate the equilibrium concentration of Ag+ (aq) in a solution that is initially 0.200 M AgNO3 and 0.800 M KCN. The formation constant for [Ag(CN)2]- (aq) is Kf = 1.0 x 10^21 *PLEASE SHOW ICE TABLE AS WELL, THANKS!!!*

Homework Answers

Answer #1
Initial (M) 0.200 0.800 0
Change (M) -x -2x x
Equilibrium (M) 0.200-x 0.800-2x x

The formation constant

On solving this polynomial equation we get x =0.2-1 \times 10^{-16}

Hence, the equilibrium concentration of silver ion is

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the equilibrium concentration of Ag+(aq ) in a solution that is initially 0.200 M AgNO3...
Calculate the equilibrium concentration of Ag+(aq ) in a solution that is initially 0.200 M AgNO3 and 0.710 M NH3, and in which the following reaction takes place: $$ (Kf = 1.70x107)
Calculate the equilbrium concentration of Zn2 (aq) in a solution that is initially 0.150 M Zn(NO3)2...
Calculate the equilbrium concentration of Zn2 (aq) in a solution that is initially 0.150 M Zn(NO3)2 and 0.800 M NaCN. The formation constant for [Zn(CN)4]2- (aq) is Kf = 2.1 x 1019. Please show all of your work and include any formulas you use! Thank you!
Calculate the [Ag+] in a solution prepared by dissolving 1.00g of AgNO3 and 10.0g KCN in...
Calculate the [Ag+] in a solution prepared by dissolving 1.00g of AgNO3 and 10.0g KCN in enough water to make a 1.00 L of solution Kf[Ag(CN)2]1-=1.0 x 1021 Answer: [Ag+] = 2.9 x 10-22M Please show the steps required to get to the answer.
Calculate The concentration of Ag+  present in solution at equilibrium when equilibrium concentration of [NH3] =0.20 M....
Calculate The concentration of Ag+  present in solution at equilibrium when equilibrium concentration of [NH3] =0.20 M. The initial Ag(NH3)2+ concentration is 0.010M. The Kf of Ag(NH3)2+ is 1.7 x 107. Ag+(aq)+ 2NH3(aq)--- >Ag(NH3)2+(aq)
Calculate the concentration of Ag+ present in solution at equilibrium when concentrated ammonia is added to...
Calculate the concentration of Ag+ present in solution at equilibrium when concentrated ammonia is added to a 0.013 M solution of AgNO3 to give an equilibrium concentration of [NH3] = 0.17 M. The formation constant for Ag(NH3)2+ at this temperature is 1.7 × 107. How do you solve a problem like this? Thanks!
Calculate the concentration of Ag+(aq) ions present at equilibrium when 10 grams of AgCl(s) is mixed...
Calculate the concentration of Ag+(aq) ions present at equilibrium when 10 grams of AgCl(s) is mixed with 300 mL of .05 M NaCl(aq). AgCl(s) <---> Ag+(aq) + Cl-(aq) Kc=1.8E-10 Please show all work! Thanks!
Calculate the concentration of H3O(aq) ions present at equilibrium in a solution that is prepared by...
Calculate the concentration of H3O(aq) ions present at equilibrium in a solution that is prepared by mixing 100 mL of .35 M HCN and 200 mL of .15 M NaCN. Kc= 6.2E-10 HCN(aq) + H2O <---> H3O(aq) + CN(aq) (this is an equation from a previous question used for this question also) Please so all work! Thanks!
For the following cell at 25 Celsius: Ag+ +e—>Ag(s)=0.80V Cu2+ +2e—>Cu(s)=0.34V (Cu(s)|CuCl2(aq)||AgNO3(aq)|Ag(s)) 1) what is the...
For the following cell at 25 Celsius: Ag+ +e—>Ag(s)=0.80V Cu2+ +2e—>Cu(s)=0.34V (Cu(s)|CuCl2(aq)||AgNO3(aq)|Ag(s)) 1) what is the equilibrium constant under standard conditions? 2)what is the cell potential if the concentration of the AgNO3 solution was changed to 0.500 M, and all other conditions remained the same? 3)Calculate delta Grxn for part 2
Calculate the concentrations of Ag+(aq) and Ni2+(aq) once the cell is “dead.” Intial concentration for both...
Calculate the concentrations of Ag+(aq) and Ni2+(aq) once the cell is “dead.” Intial concentration for both is 1.0 M Answer: [Ag+] = 2x = 4.6 × 10^−18M; [Ni2+] = 1.5 − 2.3 × 10^−18 = 1.5 M I am more interested in the work and explanation please, thanks
Calculate the formation constant Kf for Ag(cn)2- if the cell develop a potential of -0.425v. Ag(cn)2-=7.50*10^-3...
Calculate the formation constant Kf for Ag(cn)2- if the cell develop a potential of -0.425v. Ag(cn)2-=7.50*10^-3 M and CN- =0.0175 M.PLEASE SHOW STEP BY STEP .IT IS A 10 MARKS QUESTION
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT