Question

how many milliliters of h2 gas at STP are produced when 35.0mls of 1.00M HCl reacts with an excess of Al?

Answer 1

The balanced reaction is :

2Al + 6HCl ---> 3H₂ + 2AlCl₃

Therefore, 6 moles of HCl reacts with Al and produces 3 moles of H₂ gas. We have excess Al.

no. of moles of HCl = molarity x volume in L = 1 (moles/L) x 0.035 L = 0.035 moles

No. of moles of H₂ produced = no.moles of HCl/2 = 0.035 moles/ 2 = 0.0175 moles

Any gas at STP 1 mole occupies 22.4 liters of volume.

Hence, 0.0175 moles of H₂ gas occupies = 22.4 L x 0.0175 moles/ 1 mole = 0.392 L = 392 mL of H₂

The answer is 392 mL of H₂ gas produced at STP.

answered by: anonymous