Question

1) An open tubular GC column has an inner diameter of 300 micrometer and it is...

1) An open tubular GC column has an inner diameter of 300 micrometer and it is coated inside with a layer of stationary phase that is 2.0 micrometer in thickness. On this column, a derivatized form of adenosine has a retention time of 300 sec, and un-retained ethane has a sharp spike at 32 sec. Please calculate the partition coefficient for the derivatized adenosine.

Answer: 3.1*102

2)  For the same separation as described in the last question, please calculate the number of theoretical plates for the separation of the derivatized adenosine if the column length is 50 m and the peak width for the derivatized adenosine is 2.5 sec

Answer: 2.3 x 105

3) . For the same separation as described in the last question, please calculate the plate height for the separation of the derivatized adenosine.

Answer: 2.2 x 10-4 M

I wonder how they got. Can you show me step by step?

Homework Answers

Answer #1

1)

we know that

rentention factor is given by

k = ( tr- tm / tm)

so

k = ( 300-32) / 32

k = 8.375

now

b = r / 2d

where

r = column radius

d = thickness

given

r = 150 x 10-6 m

d = 2 x 10-6 m

so

b = 150 / 2 x 2

b = 37.5

now

partition coefficient = k x b = 8.375 x 37.5 = 314

so

the partition coefficient is 3.1 x 10^2

2)

we know that

N = 16 (tr/W)^2

where

N = number of theoretical plates

tr = retention time

W = peak width

given

tr = 300 sec

W = 2.5 sec

so

using given values

we get

N = 16 ( 300 / 2.5)^2

N = 230400

N = 2.304 x 10^5

so

number of theoretical plates are 2.304 x 10^5


3)

we know that

H= L / N

where

L = length of column

given

L = 50 m

so

H = 50 / 2.304 x 10^5

H = 2.17 x 10-4 m

so

the plate height is 2.2 x 10-4 m

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