Question

How many moles of Fe3+ can be reduced by 1 mL of 0.473 M hydroxylamine solution?

Answer 1

4 Fe³⁺(aq) + 2 NH₂OH(aq) -----> 4 Fe²⁺(aq) + N₂O(g) + H₂O(l) + 4 H⁺(aq)

Molarity of NH₂OH = No. of moles of NH₂OH/Volume of solution in litres

No. of moles of NH₂OH = Molarity of NH₂OH Volume of solution in litres

No. of moles of NH₂OH = 0.473 10^-3 = 4.73 10^-2 moles

Since by reaction 2 moles of NH₂OH can reduce 4 moles of Fe³⁺

4.73 10^-2 moles will reduce = (4/2) 4.73 10^-2 = 0.0946 moles of Fe³⁺

Therefore, 0.0946 moles of Fe³⁺ can be reduced by 1 mL of 0.473 M hydroxylamine solution.