Use the following pair of reduction half-reactions to design a galvanic cell. Then write in the proper coefficient for each of the species involved in the overall reaction. Water molecules and protons are not shown in the half-reactions, but may be needed in the overall reaction.
I2 (s) → I- (aq) ξo = 0.54 V
VO2+ (aq) → VO2+ (aq) ξo = 1.00 V
VO2+ (aq)
I2 (s)
VO2+ (aq)
I- (aq)
H+ (aq)
H2O (l)
I2 (s) → I- (aq) ξo = 0.54 V
VO2+ (aq) → VO2+ (aq) ξo = 1.00 V
Clearly, I2 is going to oxidize so
E° = Ered - Eox = 1-0.54 = 0.46 V
[VO2]+ (aq) = [VO]+2
I- (aq) = I2(s)
balance I
[VO2]+ (aq) = [VO]+2
2I- (aq) = I2(s)
balance O
[VO2]+ (aq) = [VO]+2 + H2O
2I- (aq) = I2(s)
balance H
2H+ +[VO2]+ (aq) = [VO]+2 + H2O
2I- (aq) = I2(s)
balance charges
e- + 2H+ +[VO2]+ (aq) = [VO]+2 + H2O
2I- (aq) = I2(s) + 2e-
balance e--
2e- + 4H+ + 2[VO2]+ (aq) = 2[VO]+2 + 2H2O
2I- (aq) = I2(s) + 2e-
add all
2I- (aq) + 2e- + 4H+ + 2[VO2]+ (aq) = 2[VO]+2 + 2H2O + I2(s) + 2e-
cancel common terms
2I- (aq) + 4H+(aq) + 2[VO2]+ (aq) = 2[VO]+2 + 2H2O(l) + I2(s)
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