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what is the pH of a 0.100M soln of H2SO4? Given Ka1= 1.70x10-2, Ka2=6.20x10-8 answer is...

what is the pH of a 0.100M soln of H2SO4? Given Ka1= 1.70x10-2, Ka2=6.20x10-8
answer is not 1.39.

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Answer #1

Using the data you are providing, the pH should be really low, Ka2 is too far from Ka1 to contribute to the pH.

Initial 0.1 0 0
change -X +X +X
equilibrium 0.1-X X X

this yields:

X=0.0336

[H+]=0.0336

pH=-log0.0336=1.47

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