Question

1.0 x 10⁷ m² of vegetation used on roofs of downtown buildings produce 100 g of C6H12O6 per square meter per year. Estimate the the annual CO2 capture

Answer 1

given that; 100 g of C6H12O6 per square meter per year, so total amount of glucose in 1.0 x 10⁷ m² = 100 g/ per square meter1.00 x 10⁷ m²

= 1*10^9 g

Now calculate the number of moles of glucose in 1*10^9 g

Number of moles = 1*10^9 g / molar mass of glucose

= 1*10^9/180.1559 g/mol

= 5550747.99 mol glucose

The formation of glucose from CO2 and H2O is as follows:

6CO2 + 6H2O -àC6H12O6 +6O2

Thus 5550747.99 mol glucose is formed by the capture of 33304487.94 mol CO2.

Now convert it into mass by its molar mass:

Molar mass of CO2 = 44.01 g/mol

33304487.94 mol CO2 *44.01 g/mol

= 1465730514 g CO2

Thus the annual CO2 capture is 1465730514 g CO2