Calculate [H+] for each of the following solutions
A) [OH−]= 3.9×10−4 M
B) [OH−]= 8.3×10−9 M
C) A solution in which [OH−] is 140 times greater than [H+]
the H+ ion concnetration is can be calculate as fololows
a) [H+] = Kw / [OH-]
[H+] = 1.0*10-14 / [OH-]
[H+] = 1.0*10-14 / 3.9*10-4
= 2.564*10-11 M
b) [H+] = 1.0*10-14 / [OH-]
[H+] = 1.0*10-14 /8.3*10-9
= 1.2048*10-6 M
c) OH- is 140 times greater so [OH-] = 140 [H+]
so 1.0*10-14 = [H+] * 140 [H+]
=> [H+]2 = 1.0*10-14 / 140
=> [H+] = 8.45*10-9 M
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