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0.250 L of 0.410 M H2SO4 is mixed with 0.200 L of 0.220 M KOH. What...

0.250 L of 0.410 M H2SO4 is mixed with 0.200 L of 0.220 M KOH. What concentration of sulfuric acid remains after neutralization?

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Answer #1

H2SO4 + 2 KOH -------> K2SO4 + 2 H2O

resulting concentration of acid = (M1V1 - M2V2)/(V1+V2)

                                                       = (0.25*0.41 - 0.2*0.22) / (0.25+0.2)

                                                       = 0.13 M

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