Assuming similar conditions, how many litres of chlorine gas react to produce 2 L of hydrogen chloride gas? H2 (g) + Cl2 → 2 HCl (g)
We can consider STP
2 L hydrogen chloride gas
PV = nRT
P = 1 atm
V = 2L
n = ?
R = Gas constant 0.0821 L atm K-1 Mol-1
T = 273
substitute in the equation and find n
1 x 2 = n x 0.0821 x 273
n = 08923 mole
0.08923 mole of hydrogen chloride gas need 0.5 equivalent (0.08923 = 0.044615 Mole ) of Cl2 gas.
Hence volume of 0.044615 mole of Cl2
P = 1 atm V = ? n = 0.044615 T = 273
1 x V = 0.044615 x 0.0821 x 273
V = 1 Lit
Hence 1 litres of chlorine gas need to react to produce 2 L of hydrogen chloride gas
give the same volume which is 2 Liter
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