For questions 1 through 3, please use the reaction: CH3Cl(g) + 3 Cl2(g) → CCl4(g) + 3 HCl(g) and experimental evidence: [CH3Cl] (M) [Cl2] (M) Initial Rate (M/s) 0.050 0.050 0.014 0.100 0.050 0.014 0.100 0.200 0.224 What is the rate law for this reaction? Rate = k [CH3Cl]2[Cl2] Rate = k [Cl2]2 Rate = k [CH3Cl] Rate = k [CH3Cl][Cl2] Rate = k [Cl2] Flag this Question Question 2 2 pts Solve for the rate of the reaction if there are 0.25 M of CH3Cl and 2.25 M of Cl2. 28.4 M/s 0.788 M/s 12.6 M/s 14.0 M/s 3.15 M/s Flag this Question Question 3 2 pts If there is initially 2.55 M of Cl2, solve for the amount of Cl2 that is present after 10 seconds. 0.0177 M 1.68 M 0.596 M 56.4 M
Get Answers For Free
Most questions answered within 1 hours.