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What is the concentration of AgCl when 325 mg is dissolved in water to give 0.500...

What is the concentration of AgCl when 325 mg is dissolved in water to give 0.500 L solution

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Answer #1

mass of AgCl = 325 mg = 325 x 10^-3 g

moles of AgCl = 325 x 10^-3 / 143.32 = 2.268 x 10^-3

volume = 0.500 L

concentration = moles / volume

                       = 2.268 x 10^-3 / 0.5

                       = 4.54 x 10^-3 M

concentration   = 4.54 x 10^-3 M

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