What is the concentration of AgCl when 325 mg is dissolved in water to give 0.500 L solution
mass of AgCl = 325 mg = 325 x 10^-3 g
moles of AgCl = 325 x 10^-3 / 143.32 = 2.268 x 10^-3
volume = 0.500 L
concentration = moles / volume
= 2.268 x 10^-3 / 0.5
= 4.54 x 10^-3 M
concentration = 4.54 x 10^-3 M
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