Question

Explain how to convert solution concentrations in molarity of ferrous ammonium sulfate to parts per million iron.

Answer 1

let. M= Molarity of Ferrsous ammonium sulfate

M= moles of ferrous ammonium sulfate/ liter of solution

Basis : 1 L of Solution

Moles of Ferrous ammonium sulfate= M

Ferrous ammonium sulfate :   (NH₄)₂Fe(SO₄)₂

M Moles of (NH4)2Fe(SO4)2 contains M moles of Fe

atomic weight of Fe= 56

Mass of Fe= M*56

Mass of M moles of   Ferrous ammonium sulfate= M*1282

282M of solution contains 56M

56/282 = 0.196gm/ 1gm of (NH4)2Fe(SO4.)2

10,00,000 gms contain 0.196*10⁶

=198582 parts/ million parts =198582ppm