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Explain how to convert solution concentrations in molarity of ferrous ammonium sulfate to parts per million...

Explain how to convert solution concentrations in molarity of ferrous ammonium sulfate to parts per million iron.

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Answer #1

let. M= Molarity of Ferrsous ammonium sulfate

M= moles of ferrous ammonium sulfate/ liter of solution

Basis : 1 L of Solution

Moles of Ferrous ammonium sulfate= M

Ferrous ammonium sulfate :   (NH4)2Fe(SO4)2

M Moles of (NH4)2Fe(SO4)2 contains M moles of Fe

atomic weight of Fe= 56

Mass of Fe= M*56

Mass of M moles of   Ferrous ammonium sulfate= M*1282

282M of solution contains 56M

56/282 = 0.196gm/ 1gm of (NH4)2Fe(SO4.)2

10,00,000 gms contain 0.196*106

=198582 parts/ million parts =198582ppm

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